Crack password protected vba project unviewable

Crack password protected vba project unviewable code#

Because the hashing algorithm generates such small hashes, 15 bits, the number of possible hashes is 2^15 = 32768 hashes.The Excel hash function maps the large space of possible passwords to the small space of possible hashes.The best description by far I've encountered of how brute forcing the Excel hashing algorithm works is on the page links to, posted by Torben Klein. This (usually) makes it more secure than simply storing the password as a string to compare against. Because of the loss of data, it is impossible to reverse a hash to get the original password, but in the future if someone types in a password it can be hashed and compared against the stored hash. A hash is a one-way algorithm that crunches up the bits, losing some information along the way, but generating a fingerprint of the original data. The Excel worksheet password protection works by converting the input password to a hash and stores it. In other words, how come this generated string of A's and B's can be used as the password to a sheet inside a particular workbook ? My question is: What kind of exploit does it use to work? If ActiveSheet.ProtectContents = False Then

Crack password protected vba project unviewable code#

I found this VBA code to unlock sheets without knowing the password: Sub PasswordBreaker()Дim i As Integer, j As Integer, k As IntegerДim l As Integer, m As Integer, n As IntegerДim i1 As Integer, i2 As Integer, i3 As IntegerДim i4 As Integer, i5 As Integer, i6 As IntegerДЇor i = 65 To 66: For j = 65 To 66: For k = 65 To 66ДЇor l = 65 To 66: For m = 65 To 66: For i1 = 65 To 66ДЇor i2 = 65 To 66: For i3 = 65 To 66: For i4 = 65 To 66ДЇor i5 = 65 To 66: For i6 = 65 To 66: For n = 32 To 126ДЄctiveSheet.Unprotect Chr(i) & Chr(j) & Chr(k) & _Д¬hr(l) & Chr(m) & Chr(i1) & Chr(i2) & Chr(i3) & _